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give an example that shows when instanteneous and average speed are the same and an example that shows when they are different .. that change in motion occurs in a freely falling object near the surface of the earth by the acceleration of gravity. a stone dropped from a tall building on earth (with an initial velocity down to zero). How fast you travel after 4.00 seconds? (Remember. and down is a = g, which is also negative). Determine the centripetal acceleration of a car making a sharp turn with a radius of 265 meters, if the vehicle is traveling at a speed of 25.0 meters per second squared. explain what effect the air friction would have on the path of a golf ball that is experiencing projectile motion near the surface of the Earth.

(I) For an object moving at constant speed is instant and average speed is the same. To accelerated motion will be different. (Ii) The force of gravity acting on the object of mass m is F = G · m · m_e / r ² (G gravitational constant mass m_e Earth, the distance r from the center of mass of the object in the center of the earth) For an object near the Earth's surface can be approximated by r the radius of the earth. => F = G · m · m_e / (r_E) ² = m · g where g = G · m_e / (r_E) ² is the acceleration of gravity of the Earth The change in time the object is equal the sum of the forces acting on it: d (m ° V) / dt = g • m <=> dv / dt = g (here v is the speed at the ground surface) (iii) dv / dt = v = t g integrate · g + c because v (t = 0) = 0> c = = 0 => v = t · g = 9.81m / s ² · 4s = 39.24m / s (iiii) acceleration centripetal is: a =- ω * R ² = v ² / r (angular velocity ω (rad / s), tangential velocity v (M / s), the distance r to the center of rotation) => A = (25m / s) ² / 265 = 2.36 / s ² (iiiii) the air friction slows the ball. Friction movement of the ball will follow a parabola. friction movement does not follow a parabolic trajectory. The maximum height and distance that the ball touches the ground will be less than the friction movement.