Posted by Cheryl | Posted in Golf Clubs | Posted on 24-10-2007
Tags: best golf clubs average golfer
Please help with a physics question?
A golfer uses a club to hit a 45-g golf ball resting on an elevated tee to the ball Leaving the golf shirt to a horizontal velocity of 38 m / s a. What is the momentum of the golf ball? b. What is the average force exerted on the club golf ball if they are in contact 2.0×10 ^ -3 C What average force is the golf ball practice in the club during this time interval? two bowling balls are identical placed 1 m away. the gravitational force between the bowling ball in 3.084×10 ^-9N a. whats the mass of the bowling ball B. compare the weight of the first ball with the gravitational force exerted on it by the second ball. Please help … my physics is taught is the worst and never explain anything!
(I think you should first read your textook) 1a Impulse = change in momentum = final momentum – initial momentum = * M / V (final) – 0 = 45/1000 * 38 kg m / s = 1.71 kg-m / s 1b Faverage * Times Delta = Impulse (see textbook!) Fav * 2e-3 = 1.71 N = 855 Fav AV Club 1c force = force on the ball Av N = 855 (ouch!) 2a Fgrav = G * m1 * m2 / R ^ 2 (Textbook by please !!!!!) 3.084E-9 = 6.6742E – 11 * M ^ 2 / 1 ^ 2 (Since M1 = M2 = m) gives m = 6.79 kg 2b Gravitational force / force of attraction mg/3.084E -9 = = = 6.78 * 9.81/3.084E-9
