Posted by Cheryl | Posted in Golf Balls | Posted on 24-10-2010
Tags: golf ball trajectory graph
parabola question when you have 3 points?
I have a parable that has to cross the points (0,0) (10,100) and (12,112). A graph to show the trajectory of a golf ball. How I can find the equation of this graph
We know that a parabola has an equation quadratic form: (x) ax ² + bx + c f Where Y, b, c are constants. However, given a point, we know now: f (0) = 0 f (10) = 100 f (12) = 112 Let's connect the first: f (0) = C = 0 c = 0 Then connect the other (and should give us an equation that we have to solve the same time). Moreover, recalling that states that c = 0: f (10) = A (10) ² + b (10) = 100 100 = 100 + 10th + 10b b = 10 m (12) = a (12) ² + b (12) 144th + 12b = 112 = 112 + 36th 3b = 28 Now we have two equations: 10th + 36th + b = 10 3b = 28 Solve the time (I'm assuming you can do it yourself). You must obtain: a = -1 / 3 b = 40 / 3 Therefore, the equation is: f (x) = (-1 / 3) x ² + (40 / 3) x
